#include stdio.h
#include conio.h
void main()
{
int i, N, sum = 0;
clrscr();
printf("Enter an integer number\n");
scanf ("%d", &N);
for (i=1; i <= N; i++)
{
sum = sum + i;
}
printf ("Sum of first %d natural numbers = %d\n", N, sum);
}
/*----------------------------------------
Output
RUN1
Enter an integer number
10
Sum of first 10 natural numbers = 55
RUN2
Enter an integer number
50
Sum of first 50 natural numbers = 1275
------------------------------------------*/
Another straight forward program which uses a for loop to increment the number. The sum value is pre instiantiated to zero and we use a for loop to increment it. The output is displayed. The other way to execute this program is using the fornula for addition of n natural numbers
2 comments:
good n easy code
Do you know how can i do the exactly same program apart from thing I want to print method of finding sum? For example, N=4
1+2=3
1+2+3=6
1+2+3+4=10
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