#include stdio.h

#include conio.h

void main()

{

int i, N, sum = 0;

clrscr();

printf("Enter an integer number\n");

scanf ("%d", &N);

for (i=1; i <= N; i++)

{

sum = sum + i;

}

printf ("Sum of first %d natural numbers = %d\n", N, sum);

}

/*----------------------------------------

Output

RUN1

Enter an integer number

10

Sum of first 10 natural numbers = 55

RUN2

Enter an integer number

50

Sum of first 50 natural numbers = 1275

------------------------------------------*/

Another straight forward program which uses a for loop to increment the number. The sum value is pre instiantiated to zero and we use a for loop to increment it. The output is displayed. The other way to execute this program is using the fornula for addition of n natural numbers

## 2 comments:

good n easy code

Do you know how can i do the exactly same program apart from thing I want to print method of finding sum? For example, N=4

1+2=3

1+2+3=6

1+2+3+4=10

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